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For the sixth time in MLB history, and the first time since 2003, there are three 100-win teams. The Dodgers still lead the pack with two games left to play, and a magic number of one to clinch potential home field advantage in the World Series.
The Astros picked up their 100th win on Friday night, putting them two games behind the Dodgers with two days remaining. The Indians, who also won on Friday, are in between.
The Dodgers were also a part of the first 100-win trio season, back in 1942 when Brooklyn won 104 games but were home watching the World Series between the 106-win Cardinals and 103-win Yankees.
MLB standings
Team | W-L | Pct | GB |
---|---|---|---|
Team | W-L | Pct | GB |
Dodgers | 102-58 | .638 | ---- |
Indians | 101-59 | .631 | 1 |
Astros | 100-60 | .625 | 2 |
The last season with three 100-win teams was 2003, when the Yankees, Braves and Giants all turning the trick. The other years with three teams in triple digits were 1977 (Royals, Phillies, Yankees), 1998 (Yankees, Braves, Astros) and 2002 (A’s, Yankees, Braves)
Back in 2017, the Dodgers beat the Indians in two of three games in June and own the tiebreaker with Cleveland. Houston has the tiebreaker with the Dodgers by virtue of a better record within their own division (yes, MLB is weird for using this).
Here is the Saturday schedule, including the Astros game against the Red Sox on Fox in the Los Angeles market:
10:05 a.m. PT: Astros (Lance McCullers Jr.) at Red Sox (Drew Pomeranz), Fox
4:10 p.m.: Indians (Corey Kluber) vs. White Sox (Carson Fulmer)
5:10 p.m.: Dodgers (Clayton Kershaw) at Rockies (German Marquez), SportsNet LA, MLB Network